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| Fully factorize the trinomial |
This is a trinomial and the directions were to fully factorize the given trinomial. When factorizing a polynomial you must first check to see if anything is in common, if yes, take it out, if no, open two sets of parentheses.
In this problem my mistake was that I automatically assumed that it was not factorisable simply because I did not think that any factors of ten could be added or subtracted to get the "invisible" 1 in the term in the center. However it is factorisable because the 3 in the first term should and can be divided into both sets of parentheses to "help" the the factors of the last term create the inner one.
In this problem my mistake was that I automatically assumed that it was not factorisable simply because I did not think that any factors of ten could be added or subtracted to get the "invisible" 1 in the term in the center. However it is factorisable because the 3 in the first term should and can be divided into both sets of parentheses to "help" the the factors of the last term create the inner one.
ShouldaCouldaWouldaTime... This is what I should have done.
3k² + k - 10
(x + 2)(3x - 5)
DON'T FORGET TO CHECK!
We check by multiplying inside terms (2 + 3k) and outside terms (-5 + k) and adding to make sure we get the inner term (1k).(2 x 3k) + (-5 x k)
6x-5x = 1k
So the answer (x + 2)(3x - 5) is correct.
And that's my answer! I really isn't that hard, especially when you have FULLY MASTERED THE CONCEPT *hint hint* like me... :)
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